document.write( "Question 526091: How many litres of fuel costing $ 1.15 per litre must be mixed with 20 litres of fuel costing $ 0.85 per litre to obtain a mixture costing $ 1 per litre. \n" ); document.write( "
Algebra.Com's Answer #348324 by Maths68(1474)\"\" \"About 
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Fuel one Amount = x
\n" ); document.write( "Fuel one Cost = $1.15 per liters
\n" ); document.write( "Fuel two Amount = 20
\n" ); document.write( "Fuel two Cost = $0.85 per liters
\n" ); document.write( "Mixture Amount= 20+x
\n" ); document.write( "Mixture cost = $1 per liters\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(Fuel one Amount)* (Fuel one Cost) + (Fuel two Amount) * (Fuel two Cost) = Mixture Amount * Mixture cost\r
\n" ); document.write( "\n" ); document.write( "x*1.15 + 20*0.85 = (20+x)*1
\n" ); document.write( "1.15x+17=20+x
\n" ); document.write( "1.15x-x=20-17
\n" ); document.write( "0.15x=3
\n" ); document.write( "x=3/0.15
\n" ); document.write( "x=20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Fuel one Amount = x = 20 liters
\n" ); document.write( "Fuel one Cost = $1.15 per liters
\n" ); document.write( "Fuel two Amount = 20
\n" ); document.write( "Fuel two Cost = $0.85 per liters
\n" ); document.write( "Mixture Amount= 20+20 = 20+6 = 40 liters
\n" ); document.write( "Misture cost = $1 per liters\r
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\n" ); document.write( "\n" ); document.write( "20 litres of fuel costing $ 1.15 per litre must be mixed with 20 litres of fuel costing $ 0.85 per litre to obtain a mixture of 40 liters fuel costing $ 1 per litre.
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