document.write( "Question 526076: The area is 44 square feet, and twice the length is 5 feet shorter than two times the width. What is the perimeter?
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Algebra.Com's Answer #348312 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! The area is 44 square feet, and twice the length is 5 feet shorter than two times the width. What is the perimeter?\r \n" ); document.write( "\n" ); document.write( "Area = A = 4 ft^2 \n" ); document.write( "Length = 2l = (2w-5)ft \n" ); document.write( "Length = l = (2w-5)/2 ft \n" ); document.write( "Length = ? \n" ); document.write( "Width = ?\r \n" ); document.write( "\n" ); document.write( "Length * Width = Area of Rectangle \n" ); document.write( "l*w=A \n" ); document.write( "((2w-5)/2)*(w) = 44 \n" ); document.write( "(2w^2-5w)/2 = 44 \n" ); document.write( "(2w^2-5w) = 44*2 \n" ); document.write( "2w^2-5w = 88 \n" ); document.write( "2w^2-5w-88=0\r \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "w=-5.5 not possible \n" ); document.write( "w=8\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Length = 2l = (2w-5)ft \n" ); document.write( "Length = l = (2w-5)/2 = (2(8)-5)/2=(16-5)/2=11/2=5.5ft\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Length = 5.5 ft \n" ); document.write( "Width = 8 ft \n" ); document.write( " \n" ); document.write( " |