document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=526017>Question 526017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve the problem: a varies jointly with b and c. if a=120 b=8 and c=5 write an equation relating the variables then solve for a when b=-4 and c=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348292 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  a varies jointly with b and c. if a=120 b=8 and c=5 write an equation relating the variables then solve for a when b=-4 and c=9<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "a = kb*c<BR>\n" );
document.write( "----<BR>\n" );
document.write( "solve for \"k\" using a = 120 when b = 8 and c = 5<BR>\n" );
document.write( "120 = k*8*5<BR>\n" );
document.write( "k = 3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "a = 3*b*c<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Solve for \"a\" when b = -4 and c = 9<BR>\n" );
document.write( "a = 3*-4*9<BR>\n" );
document.write( "a = -108<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );