document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52239>Question 52239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> separate 72 into two parts, one of which shall be 1/3 of the other </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34825 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B%281%2F3%29x=72 ALIGN=MIDDLE  ALT=\"x%2B%281%2F3%29x=72\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Solving for x, we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%2F3%29x=72 ALIGN=MIDDLE  ALT=\"%284%2F3%29x=72\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now multiply both sides by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > and we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=54 ALIGN=MIDDLE  ALT=\"x=54\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  That means our first number is 54.  The second number is obtained by finding 72-54, which is 18; 18 is one-third of 54, so we have the correct answers of 54 and 18. </SPAN>\n" );
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