document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=525814>Question 525814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of an equilateral hexagon is 4 inches less than the the length of a side of a square. The perimeter of the hexagon is equal to the perimeter of the square. Find the length of a side of the hexagon and the length of a side of the square.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348225 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the side of the square = x, then the length of the side of the equilateral (regular) hexagon (six-sided polygon) is (x-4), so...<BR>\n" );
document.write( "For the square, the perimeter (P) is:<BR>\n" );
document.write( "P = 4x.<BR>\n" );
document.write( "For the regular hexagon, the perimeter (P) is:<BR>\n" );
document.write( "P = 6(x-4). Set the two perimeters equal.<BR>\n" );
document.write( "6(x-4) = 4x Simplify and solve for x.<BR>\n" );
document.write( "6x-24 = 4x<BR>\n" );
document.write( "2x = 24<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "The length of a side of the square = 12 inches.<BR>\n" );
document.write( "The length of a side of the regular hexagon = x-4 = 12-4 = 8 inches. </SPAN>\n" );
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