document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52267>Question 52267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area and perimeter of: 12m in length, 4m in width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34821 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is given as lw, where l is the length and w is the width; in this case, that's 12*4, which is 48 square meters.  The perimeter is 2(l+w) or in this case, 2(12+4), or 32m. </SPAN>\n" );
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