document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=525641>Question 525641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, the longest side is double the shortest side and the third side is 3 cm less than the longest side. If the perimeter of the triangle is 57 cm, find all sides of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348171 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let<BR>\n" );
document.write( "Shortest side = x cm<BR>\n" );
document.write( "Longest side = 2x cm<BR>\n" );
document.write( "Third side = 2x-3 cm <BR>\n" );
document.write( "Given<BR>\n" );
document.write( "Perimeter = 57cm\r<BR>\n" );
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document.write( "Longest side + Shortest side + Third side = Perimeter of Triangle<BR>\n" );
document.write( "2x+x+(2x-3)=57<BR>\n" );
document.write( "3x+2x-3=57<BR>\n" );
document.write( "5x=57+3<BR>\n" );
document.write( "5x=60<BR>\n" );
document.write( "x=60/5<BR>\n" );
document.write( "x=12\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( "Shortest side = x = 12 cm<BR>\n" );
document.write( "Longest side = 2x = 12*2= 24 cm<BR>\n" );
document.write( "Third side = 2x-3 cm = 24 - 3 = 21 cm<BR>\n" );
document.write( " </SPAN>\n" );
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