document.write( "Question 525559: total of three numbers is 174. If the ratio between 1st and 3rd number is 1:4. And the ratio between 2nd and 3rd number is 9:16. Then what is the 2nd number? \n" ); document.write( "
Algebra.Com's Answer #348147 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for each statement. Simplify each equation as much as you can.
\n" ); document.write( "We want to get a & b in terms of a.
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\n" ); document.write( "total of three numbers is 174.
\n" ); document.write( "a + b + c = 174
\n" ); document.write( ":
\n" ); document.write( " If the ratio between 1st and 3rd number is 1:4.
\n" ); document.write( "\"a%2Fc\" = \"1%2F4\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "c = 4a
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\n" ); document.write( " And the ratio between 2nd and 3rd number is 9:16.
\n" ); document.write( "\"b%2Fc\" = \"9%2F16\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "16b = 9c
\n" ); document.write( "replace c with 4a
\n" ); document.write( "16b = 9(4a)
\n" ); document.write( "16b = 36a
\n" ); document.write( "Divide both sides by 16
\n" ); document.write( "b = \"36%2F16\"a
\n" ); document.write( "Reduce fraction
\n" ); document.write( "b = \"9%2F4\"a\r
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\n" ); document.write( "Substitute in the 1st equation
\n" ); document.write( "a + \"9%2F4\"a + 4a = 174
\n" ); document.write( "multiply by 4 to get rid of denominators:
\n" ); document.write( "4a + 9a + 4(4a) = 4(174)
\n" ); document.write( "4a + 9a + 16a = 696
\n" ); document.write( "29a = 696
\n" ); document.write( "a = \"696%2F29\"
\n" ); document.write( "a = 24 is the 1st number
\n" ); document.write( "Find the 2nd number
\n" ); document.write( "b = \"9%2F4\"(24)
\n" ); document.write( "b = 9*6
\n" ); document.write( "b = 54 is the 2nd number, which is what they want here
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\n" ); document.write( "Find the 3rd number to check the solutions in the 1st equation
\n" ); document.write( "c =4(24)
\n" ); document.write( "c = 96
\n" ); document.write( "24 + 54 + 96 = 174, confirms our solutions\r
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