document.write( "Question 525231: Solve for x:
\n" ); document.write( "2 log base 5(7-x)-log base 5 3=log base 5 12 \n" ); document.write( "
Algebra.Com's Answer #348138 by lwsshak3(11628)\"\" \"About 
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Solve for x:
\n" ); document.write( "2 log base 5(7-x)-log base 5 3=log base 5 12
\n" ); document.write( "log5(7-x)^2-log5(3)-log5(12)=0
\n" ); document.write( "log5(7-x)^2-[(log5(3)+log5(12)]=0
\n" ); document.write( "place under single log
\n" ); document.write( "log5[(7-x)^2/3*12]=0
\n" ); document.write( "log5[(7-x)^2/36]=0
\n" ); document.write( "convert to exponential form: base(5) raised to log of number(0)=number(7-x)^2/36)
\n" ); document.write( "5^0=(7-x)^2/36=1
\n" ); document.write( "(7-x)^2=36
\n" ); document.write( "take sqrt of both sides
\n" ); document.write( "7-x=±√36=±6
\n" ); document.write( "x=7±6
\n" ); document.write( "x=1
\n" ); document.write( "or
\n" ); document.write( "x=13(reject,(7-x)>0 \n" ); document.write( "
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