document.write( "Question 525500: Jaya has $16,000 to invest. She invests part of it in an account paying 6% simple interest and the rest in an account paying 7% simple interest. If her annual income is $1080, how much does she have invested in each account? \n" ); document.write( "

Algebra.Com's Answer #348134 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "She invests at 6% = x
\n" ); document.write( "She invests at 7% = 16000-x
\n" ); document.write( "Given
\n" ); document.write( "Total Amount invested = 16000
\n" ); document.write( "Total Annual income = 1080\r
\n" ); document.write( "\n" ); document.write( "(Amount invested at 6%) * (6%) + (Amount invested at 7%)( 7%)=Total income \r
\n" ); document.write( "\n" ); document.write( "x*6/100 + (16000-x)*7/100=1080
\n" ); document.write( "Multiply by 100 both sides
\n" ); document.write( "x*6 + (16000-x)*7=1080*100
\n" ); document.write( "6x+112000-7x=108000
\n" ); document.write( "-x=108000-112000
\n" ); document.write( "-x=-4000
\n" ); document.write( "Multiply by -1 both sides
\n" ); document.write( "x=4000\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "She invests at 6% = x = 4000
\n" ); document.write( "She invests at 7% = 16000-x = 16000-4000=12000\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "======
\n" ); document.write( "4000*6/100 + 12000*7/100=1080
\n" ); document.write( "40*6+120+7=1080
\n" ); document.write( "240 + 840 = 1080
\n" ); document.write( "1080=1080 \n" ); document.write( "

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