document.write( "Question 52249: If given the equation: \"h=%28-16t%5E2%29%2B560t\", when does h become 0? \n" ); document.write( "
Algebra.Com's Answer #34813 by rchill(405)\"\" \"About 
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Substitute 0 in for h and solve: \"0=%28-16t%5E2%29%2B560t\". Now factor that into \"0=-16t%28t-35%29\". That means that either \"-16t=0\" or \"t-35=0\", as either factor can be 0. Solving for each shows us that for the first equation that \"t=0\", and for the second \"t=35\". \n" ); document.write( "
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