document.write( "Question 525473: NATURAL LOGARITHMS: ln (1/e)= -1 -----why?\r
\n" ); document.write( "\n" ); document.write( "i've looked through my book and it lists the natural logarithms properties but i can't find why ln (1/e)= -1 ... right of the bat, i went \"oh, -1\", but i can't find a logical step-by-step process to explain why the answer is -1... any help?
\n" ); document.write( "

Algebra.Com's Answer #348115 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
ln (1/e)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ln (1) - ln(e) .... Using the idea that ln(x/y) = ln(x)-ln(y)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "0 - ln(e) ... Since ln(1) = 0\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-ln(e)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-(1) .... because ln(e) = 1 by definition\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-1\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So ln(1/e) = -1
\n" ); document.write( "
\n" );