document.write( "Question 52264: Solve for a if c=abx. and\r
\n" ); document.write( "\n" ); document.write( "solve for x: -3(x-5)=15 \n" ); document.write( "

Algebra.Com's Answer #34809 by rchill(405) $\"\"$ $\"About$

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To solve for a, you need to have $\"a\"$ isolated on either the left or right side of the equals sign. To do that in this case, divide both sides by $\"bx\"$ , thusly: $\"c%2F%28bx%29=%28abx%29%2F%28bx%29\"$ , which simplifies to $\"c%2F%28bx%29=a\"$ . For the second equation, expand it: $\"-3%2Ax%2B%28-3%29%2A%28-5%29=15\"$ , which simplifies to $\"-3x%2B15=15\"$ . Now subtract both sides by 15 to get $\"-3x%2B15-15=15-15\"$ which simplifies to $\"-3x=0\"$ . Dividing both sides by -3: $\"%28-3x%29%2F-3=0%2F-3\"$ , which simplifies to $\"x=0\"$ . \n" ); document.write( "

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