document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=525358>Question 525358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3m  longer than its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is 34m  , find its area.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348080 by </B><A HREF=/tutors/aboutme.mpl?userid=simranb><B>simranb(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=simranb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=simranb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,Hope you find your answer,<BR>\n" );
document.write( "Let the width be x<BR>\n" );
document.write( "then the length would be x+3<BR>\n" );
document.write( "Then Perimeter=2(l+b)=34<BR>\n" );
document.write( "2(x+x+3)=34<BR>\n" );
document.write( "2(2x+3)=34<BR>\n" );
document.write( "4x+6=34<BR>\n" );
document.write( "4x=34-6<BR>\n" );
document.write( "4x=28<BR>\n" );
document.write( "x=28/4<BR>\n" );
document.write( "x=7<BR>\n" );
document.write( "Then the length =x+3<BR>\n" );
document.write( "                 =7+3=10m<BR>\n" );
document.write( "Width = x =7m<BR>\n" );
document.write( "Area = l * b<BR>\n" );
document.write( "     = 10 * 7<BR>\n" );
document.write( "     = 70sqm<BR>\n" );
document.write( "Cheers!<BR>\n" );
document.write( "Simran </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );