document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=525377>Question 525377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please answer the following. \"A rectangle has a perimeter of 38 feet and an area of 48 square feet. What are the dimensions of the rectangle\"? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #348079 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=348079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(L+W) = 38<BR>\n" );
document.write( "L*W = 48<BR>\n" );
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document.write( "W = 48/L<BR>\n" );
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document.write( "substitute<BR>\n" );
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document.write( "2(L+48/L) = 38<BR>\n" );
document.write( "2L +96/L = 38<BR>\n" );
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document.write( "multiply both sides by L to eliminate the fraction<BR>\n" );
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document.write( "2L^2 +96 = 38L<BR>\n" );
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document.write( "2L^2 -38L +96 = 0<BR>\n" );
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document.write( "divide by 2<BR>\n" );
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document.write( "L^2 -19L +48 = 0<BR>\n" );
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document.write( "factor<BR>\n" );
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document.write( "(L-3)(L-16) = 0<BR>\n" );
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document.write( "L = 3 or L=16<BR>\n" );
document.write( "so<BR>\n" );
document.write( "W = 16 or 3, respectively<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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