document.write( "Question 525369: Four times the first of three consecutive even integers is sixteen more than three times the second. Find the integers \n" ); document.write( "

Algebra.Com's Answer #348072 by oberobic(2304) $\"\"$ $\"About$

You can put this solution on YOUR website!
There are three consecutive even integers. Define these as:
\n" ); document.write( "x
\n" ); document.write( "x+2
\n" ); document.write( "x+4
\n" ); document.write( ".
\n" ); document.write( "4x - 16 = 3*(x+2)
\n" ); document.write( "4x -16 = 3x + 6
\n" ); document.write( "x = 22
\n" ); document.write( ".
\n" ); document.write( "x+2 = 24
\n" ); document.write( ".
\n" ); document.write( "x+4 = 26
\n" ); document.write( ".
\n" ); document.write( "Check the answer.
\n" ); document.write( "4x = 4*22 = 88
\n" ); document.write( "88 -16 = 72
\n" ); document.write( "3*24 = 72
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Answer: The three consecutive even integers are: 22, 24, and 26.
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "

\n" );