document.write( "Question 525282: keil is going to mke 10 pounds of mixed nuts for a party. If Keil can spend $47.50 on nuts and peanuts cost $2.00 per pound and fancey nuts cost 7.50 per pound, how many pounds of each should he buy? \n" ); document.write( "

Algebra.Com's Answer #348038 by oberobic(2304) $\"\"$ $\"About$

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p = lb of peanuts
\n" ); document.write( "200p = cost of peanuts in cents
\n" ); document.write( "f = lb of fancy nuts
\n" ); document.write( "750f = cost of fancy nuts in cents
\n" ); document.write( ".
\n" ); document.write( "4750 cents is the budget
\n" ); document.write( ".
\n" ); document.write( "200p + 750f = 4750
\n" ); document.write( ".
\n" ); document.write( "p + f = 10
\n" ); document.write( "so
\n" ); document.write( "p = 10-f
\n" ); document.write( ".
\n" ); document.write( "Substitute
\n" ); document.write( ".
\n" ); document.write( "200(10-f) + 750f = 4750
\n" ); document.write( "2000 -200f +750f = 4750
\n" ); document.write( "550f = 2750
\n" ); document.write( "f = 5
\n" ); document.write( ".
\n" ); document.write( "p = 10-f
\n" ); document.write( "p = 10-5
\n" ); document.write( "p = 5
\n" ); document.write( ".
\n" ); document.write( "Check the budget.
\n" ); document.write( "200p = 200*5 = 1000
\n" ); document.write( "750f = 750*5 = 3750
\n" ); document.write( "1000 + 3750 = 4750
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Answer: 5 lb of peanuts and 5 lb of fancy nuts will make 10 lb of mix at a cost of $47.50.
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "

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