document.write( "Question 52254: y=2/3x -3\r
\n" ); document.write( "\n" ); document.write( "i know this is in y=m (x) + b but i don't know where to start.
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Algebra.Com's Answer #34802 by tutorcecilia(2152)\"\" \"About 
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y= 2/3x -3 [This is in the slope-intercept form of a line: y=mx+b]
\n" ); document.write( "y=any value of y on the line
\n" ); document.write( "m=the slope of the line
\n" ); document.write( "x=any corresponding value of x on the line
\n" ); document.write( "b=the y-intercept--where the line crosses the y-axis
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\n" ); document.write( "So, plot the the y=intercept at coordinate point (0, -3). Starting at (0,-3) and using the slope of (+2/+3), move up 2 spaces and move 3 spaces to the right. Plot this point. Starting over at (0, -3), and using the slope of (-2/-3), move down 2 spaces and 3 spaces to the left. Plot this point. Connect the dots for the representation of the line.\r
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\n" ); document.write( "To find where the line crosses the x-axis, let y=0 and solve for x:
\n" ); document.write( "y=2/3x -3
\n" ); document.write( "0=2/3x -3
\n" ); document.write( "3=2/3x
\n" ); document.write( "9/2=x
\n" ); document.write( "So, the x-intercept = (9/2, 0)\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+%282%2F3%29x+-3%29+\"
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