document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52231>Question 52231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi i have a few questions.<BR>\n" );
document.write( "1. which is the larger number 2.0x10^2 or 2.0x10^-3?\r<BR>\n" );
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document.write( "2.Convert 27% to a FRACTION\r<BR>\n" );
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document.write( "3. If PV=gRT/M evaluate M\r<BR>\n" );
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document.write( "4. If d=1.5g/ml and m=3.0g find v in d=m/v\r<BR>\n" );
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document.write( "5.If P1/T1=P2/T2 evaluate T2\r<BR>\n" );
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document.write( "6. The number 32 is two thirds of what number?\r<BR>\n" );
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document.write( "7. Convert 151K to Celcius using formula K=273+celcius </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34798 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 2x10^2=200 and 2x10^-3=.002, 200 is larger than .002, so 2x10^2 is larger than 2X10^-3<BR>\n" );
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document.write( "2. 27%=27/100<BR>\n" );
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document.write( "3. PV=gRT/M<BR>\n" );
document.write( "M(PV)=M(gRT/M)<BR>\n" );
document.write( "MPV=gRT<BR>\n" );
document.write( "MPV/PV=gRT/PV<BR>\n" );
document.write( "M=gRT/PV<BR>\n" );
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document.write( "4.  d=m/v<BR>\n" );
document.write( "v(d)=v(m/v)<BR>\n" );
document.write( "vd=m<BR>\n" );
document.write( "vd/d=m/d<BR>\n" );
document.write( "v=m/d<BR>\n" );
document.write( "m=3.0g and d=1.5g/ml substitute these values into the formula<BR>\n" );
document.write( "v=3.0g/1.5g/ml<BR>\n" );
document.write( "v=2ml<BR>\n" );
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document.write( "5. P1/T1=P2/T2  Cross multiply.<BR>\n" );
document.write( "P1T2=P2T1<BR>\n" );
document.write( "P1T2/P1=P2T1/P1<BR>\n" );
document.write( "T2=P2T1/P1<BR>\n" );
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document.write( "6.  32=(2/3)x<BR>\n" );
document.write( "(3/2)(32)=(3/2)(2/3)x<BR>\n" );
document.write( "96/2=6/6x<BR>\n" );
document.write( "48=x<BR>\n" );
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document.write( "7.  151=273+C<BR>\n" );
document.write( "-273+151=-273+273+C<BR>\n" );
document.write( "-122=C<BR>\n" );
document.write( "C=-122 degrees celsius\r<BR>\n" );
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document.write( "   </SPAN>\n" );
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