document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524941>Question 524941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the original price of an item decreased 60% and a new price of $840 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347972 by </B><A HREF=/tutors/aboutme.mpl?userid=lagbens><B>lagbens(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lagbens><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lagbens><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the item decreased %6o, then this new price represents %40                         if %40----$840<BR>\n" );
document.write( "   %60----$X  (x rep. the amount of money)<BR>\n" );
document.write( "we can cross multiply to find x(60 times 840 divided by 40)<BR>\n" );
document.write( "=$1260.<BR>\n" );
document.write( "so the original price of the item  is given by adding $840 to $1260<BR>\n" );
document.write( "=$2100 (final answer)           </SPAN>\n" );
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