document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524868>Question 524868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars started at the same time from the same hotel and drove in opposite directions. One drove 20 miles per hour faster than the other. If they were 330 miles apart in 3 hours, find the speed of each car. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347952 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Car A Speed = a mph<BR>\n" );
document.write( "Car B Speed = a+20 mph\r<BR>\n" );
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document.write( "Car A will travel total distance = a * 3 = 3a mph<BR>\n" );
document.write( "Car B will travel total distance = (a+20) * 3 = 3a+60 mph\r<BR>\n" );
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document.write( "They are traveling in oppisite directions so <BR>\n" );
document.write( "sum of the distance travelled by both Cars = 330 miles\r<BR>\n" );
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document.write( "3a+3a+60=330<BR>\n" );
document.write( "6a=330-60<BR>\n" );
document.write( "6a=270<BR>\n" );
document.write( "6a/6=270/6<BR>\n" );
document.write( "a=45\r<BR>\n" );
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document.write( "Car A Speed = a=45 mph<BR>\n" );
document.write( "Car B Speed = a+20=45+20=65 mph\r<BR>\n" );
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document.write( "Check\r<BR>\n" );
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document.write( "Distance travelled by Car A = 45 * 3 = 135 miles<BR>\n" );
document.write( "Distance travelled by Car B = 65*3 = 195 miles<BR>\n" );
document.write( "Total Distance b/w Car A and B = 135+139 = 330 miles </SPAN>\n" );
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