document.write( "Question 524836: two boats leave san diego at the same time. one boat sails due north and the due west. when they are 10 miles apart, the boat traveling north has sailed 2 miles farther than the boat sailing west.find the distance each boat has traveled. \n" ); document.write( "
Algebra.Com's Answer #347948 by mananth(16946)\"\" \"About 
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The boats are travelling at right angles\r
\n" ); document.write( "\n" ); document.write( "At any given time if you draw a line from the starting point to the boats and draw a line joining the two boats they form a right triangle\r
\n" ); document.write( "\n" ); document.write( "distance = 10 miles this is the hypotenuse \r
\n" ); document.write( "\n" ); document.write( "let west bound boat be at x miles from starting point
\n" ); document.write( "other boat is x+2 miles from origin\r
\n" ); document.write( "\n" ); document.write( "x^2+(x+2)^2=10^2\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2+4x+4=100
\n" ); document.write( "2x^2+4x-96 = 0
\n" ); document.write( "/2
\n" ); document.write( "x^2+2x-48=0
\n" ); document.write( "x^2+8x-6x-48=0
\n" ); document.write( "x(x+8)-6(x+80=0
\n" ); document.write( "(x+8)(x-6)=0
\n" ); document.write( "S0 x=6 \r
\n" ); document.write( "\n" ); document.write( "west bound boat is 6 miles
\n" ); document.write( "North bound boat is 8 miles from origin\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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