document.write( "Question 524860: Two number differ by 2 the sum of their squares is 244 find the number. \n" ); document.write( "
Algebra.Com's Answer #347942 by mananth(16946)\"\" \"About 
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let the numbers be x & y
\n" ); document.write( "x-y=2
\n" ); document.write( "x=(y+2)\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2=244
\n" ); document.write( "(y+2)^2+y^2=244\r
\n" ); document.write( "\n" ); document.write( "y^2+4y+4 +y^2=244
\n" ); document.write( "2y^2+4y-240=0\r
\n" ); document.write( "\n" ); document.write( "/2
\n" ); document.write( "y^2+2y-120=0
\n" ); document.write( "y^2+12y-10y-120=0
\n" ); document.write( "y(y+12)-10(y+12)=0
\n" ); document.write( "(y-10)(y+12)=0\r
\n" ); document.write( "\n" ); document.write( "y= 10 OR -12\r
\n" ); document.write( "\n" ); document.write( "plug values of y in first equation
\n" ); document.write( "x-y=2\r
\n" ); document.write( "\n" ); document.write( "when y=10 x=12 (12,10)\r
\n" ); document.write( "\n" ); document.write( "when y=-12
\n" ); document.write( "x=-10
\n" ); document.write( "(-10,-12)\r
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