document.write( "Question 524858: A plane traveled 1089 miles to Houston and back. The trp there was with the wind. It took 9 hours.The trip back was into the wind. The trip back took 11 hours. What is the speed of the plane in still air? what is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #347941 by mananth(16946)\"\" \"About 
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Plane speed= x mph
\n" ); document.write( "Wind speed= y mph
\n" ); document.write( "with wind (x+y)
\n" ); document.write( "against wind (x-y)
\n" ); document.write( "d= 1089 with Wind
\n" ); document.write( "1089 / (x+y) = 9
\n" ); document.write( "divide by 9
\n" ); document.write( "121 / (x+y) = 1
\n" ); document.write( "(x+y) = 121 ............1
\n" ); document.write( "d= = 1089 against wind
\n" ); document.write( "1089 /(x-y)= 11
\n" ); document.write( "divide by 11
\n" ); document.write( "99 /(x-y) = 1
\n" ); document.write( " x - y =99
\n" ); document.write( "add up (1) & (2)
\n" ); document.write( "2 x = 220
\n" ); document.write( "/ 2
\n" ); document.write( "x= 110 mph speed of Plane
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "we get y= 11 mph speed of Wind
\n" ); document.write( "m.ananth@hotmail.ca
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