document.write( "Question 524758: Tom is 10 years older than Pat. In 6 years. Tom will be 1.5 times as old as Pat will be then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #347900 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! T = P + 10 \n" ); document.write( ". \n" ); document.write( "In 6 years, \n" ); document.write( "T+6 \n" ); document.write( "P+6 \n" ); document.write( ". \n" ); document.write( "T+6 = 1.5(P+6) \n" ); document.write( ". \n" ); document.write( "Substitute for T \n" ); document.write( ". \n" ); document.write( "(P+10) + 6 = 1.5P + 9 \n" ); document.write( "P +16 = 1.5P + 9 \n" ); document.write( "-.5P = -7 \n" ); document.write( "P = 14 = Pat's age \n" ); document.write( ". \n" ); document.write( "T = P+10 = Tom's age \n" ); document.write( "T = 24 \n" ); document.write( ". \n" ); document.write( "Check the values in 6 years. \n" ); document.write( ". \n" ); document.write( "30 = 1.5(20) ? \n" ); document.write( "Yes \n" ); document.write( ". \n" ); document.write( "Answer: Pat is 14 and Tom is 24. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |