document.write( "Question 524746: Can you please help me with this problem? I have to find the equation of the line that passes through the point (2,5) and is perpendicular to the line x-2y=5
\n" ); document.write( "The final answer has to be in slope-intercept form. \n" ); document.write( "

Algebra.Com's Answer #347891 by mananth(16946) $\"\"$ $\"About$

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1 x -2 y = 5
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-2 y = -1 x + 5
\n" ); document.write( "Divide by -2
\n" ); document.write( " y = 1 x + -2.5
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 1/2
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be -2
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\n" ); document.write( "m= -2 ,point ( 2 , 5 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "5 = -4.00 + b
\n" ); document.write( "b= 9
\n" ); document.write( "m= -2
\n" ); document.write( "The required equation is y =-2 x + 9
\n" ); document.write( "m.ananth@hotmail.ca
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