document.write( "Question 52216: Sally bought 3 chocolate bars and a pack of gum and paid $1.75. Jake bought 2 chocolate bars and 4 packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum. \n" ); document.write( "
Algebra.Com's Answer #34789 by tutorcecilia(2152)\"\" \"About 
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3 choco. + 1 gum = $1.75
\n" ); document.write( "2 choco. + 4 guns = $2.00
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\n" ); document.write( "Re-writing:
\n" ); document.write( "3x + 1y = 1.75
\n" ); document.write( "2x + 4y = 2.00
\n" ); document.write( "Solve using any method for solving a system of equations.
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\n" ); document.write( "\n" ); document.write( "Using the method of elimination to solve:
\n" ); document.write( "-2(3x + 1y = 1.75)
\n" ); document.write( "+3(2x + 4y = 2.00)
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\n" ); document.write( "-6x-2y=-3.5
\n" ); document.write( "+6x+12y=6
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\n" ); document.write( "0x+10y=2.5
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\n" ); document.write( "10y=2.5 [Solve for y]
\n" ); document.write( "y=.25 cents per gum
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\n" ); document.write( "Plug y=.25 back into either of the original equations
\n" ); document.write( "3x + 1(.25) = 1.75 [Solve for x]
\n" ); document.write( "3x+.25=1.75
\n" ); document.write( "x=.50 cents per chocolate bar.
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\n" ); document.write( "Checking:
\n" ); document.write( "3x + 1y = 1.75 [Plug-in x=.50 and y=.25]
\n" ); document.write( "3(.50) + 1(.25) = 1.75
\n" ); document.write( "1.75=1.75 [Checks out]
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\n" ); document.write( "Checking
\n" ); document.write( "2x + 4y = 2.00 [Plug-in x=.50 and y=.25]
\n" ); document.write( "2(.50)+4(.25)=2.00
\n" ); document.write( "2=2 [checks out]
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