document.write( "Question 524114: At 1:00 p.m. a car leaves St. Louis for Chicago,
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document.write( "traveling at a constant speed of 65 miles per hour. At
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document.write( "2:00 p.m. a truck leaves Chicago for St. Louis,
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document.write( "traveling at a constant speed of 55 miles per hour. If it
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document.write( "is a 305-mile drive between St. Louis and Chicago, at
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document.write( "what time will the car and truck pass each other? \n" );
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Algebra.Com's Answer #347875 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 miles per hour. \n" ); document.write( " At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant speed of 55 miles per hour. \n" ); document.write( " If it is a 305-mile drive between St. Louis and Chicago, at what time will the car and truck pass each other? \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the car \n" ); document.write( "then \n" ); document.write( "(t-1) = travel time of the truck \n" ); document.write( ": \n" ); document.write( "Write a distance equation, dist = speed * time \n" ); document.write( ": \n" ); document.write( "When they meet, the sum of their distance traveled will be 305 mi \n" ); document.write( ": \n" ); document.write( "Car dist + Truck dist = 305 mi \n" ); document.write( "65t + 55(t-1) = 305 \n" ); document.write( "65t + 55t - 55 = 305 \n" ); document.write( "65t + 55t = 305 + 55 \n" ); document.write( "120t = 360 \n" ); document.write( "t = 360/120 \n" ); document.write( "t = 3 hrs \n" ); document.write( "Find the time of the meeting: 1:00 + 3:00 = 4 PM \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this, find the distance each traveled \n" ); document.write( "65(3) = 195 mi \n" ); document.write( "55(2) = 110 mi \n" ); document.write( "--------------- \n" ); document.write( "tot dist:305 mi \n" ); document.write( " \n" ); document.write( " |