document.write( "Question 524241: I am a three digit number less than 200. When I am divided by 2,3,6,7 and 9,
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document.write( "there is a remainder of 1. What bumber am I? \n" );
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Algebra.Com's Answer #347719 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! In order to leave a remainder of 1 when divided by any of \n" ); document.write( "2,3,6,7, and 9, you have to be 1 more than a common multiple \n" ); document.write( "of 2,3,6,7 and 9\r \n" ); document.write( "\n" ); document.write( "2 = 2 \n" ); document.write( "3 = 3 \n" ); document.write( "6 = 2*3 \n" ); document.write( "7 = 7 \n" ); document.write( "9 = 3*3\r \n" ); document.write( "\n" ); document.write( "The least common multiple of all those is 2*3*3*7 = 126\r \n" ); document.write( "\n" ); document.write( "The next common multiple of all those is twice that or 252, \n" ); document.write( "which is more than 200. \r \n" ); document.write( "\n" ); document.write( "But you are less than 200.\r \n" ); document.write( "\n" ); document.write( "So you are 1 more than 126, so you are 127.\r \n" ); document.write( "\n" ); document.write( "Edwin \n" ); document.write( " |