document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524385>Question 524385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of each of a 10% acid solution and a 25% acid solution must be used to produce 60 liters of a 15% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347716 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of each of a 10% acid solution and a 25% acid solution must be used to produce 60 liters of a 15% acid solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.10x + 0.25(60-x) = 0.15*60<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "10x + 25*60-25x = 15*60<BR>\n" );
document.write( "-15x = -10*50<BR>\n" );
document.write( "x = (2/3)*50<BR>\n" );
document.write( "x = 33 1/3 liters (amt. of 10% solution needed)<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "60-x = 26 2/3 liters (amt. of 25% solution needed)<BR>\n" );
document.write( "=====================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );