document.write( "Question 524345: I need help with this please...There is the main question needing an answer with demonstration and I need an example please!!! Thank you!!!\r
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\n" ); document.write( "\n" ); document.write( "A) How do you know if a quadratic equation will have one, two, or no solutions?\r
\n" ); document.write( "\n" ); document.write( "B) Demonstrate the process in detail with your own example.\r
\n" ); document.write( "\n" ); document.write( "C) Provide an example. \n" ); document.write( "

Algebra.Com's Answer #347710 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
A) Examine the \"discriminant\" This is the quantity under the radical sign in the quadratic formula: $\"b%5E2-4ac\"$ .
\n" ); document.write( "a) If the discriminant is zero $\"b%5E2-4ac+=+0\"$ there is \"one\" solution!
\n" ); document.write( "N.B. There are really two roots but they are identical.
\n" ); document.write( "B) If the discriminant is positive $\"b%5E2-4ac+%3E+0\"$ there are two real roots.
\n" ); document.write( "C) If the discriminant is negative $\"b%5E2-4ac+%3C+0\"$ there are \"no\" real solutions.
\n" ); document.write( "N.B. The solutions in this case are complex roots.
\n" ); document.write( "B) Here's an example:
\n" ); document.write( " $\"4x%5E2%2B6x-3+=+0\"$ Here: a = 4, b = 6, and c = -3, so
\n" ); document.write( " $\"b%5E2-4ac+=+36-4%284%29%28-3%29\"$ = $\"84\"$
\n" ); document.write( "The discriminant is positive so there are two real roots. \n" ); document.write( "

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