document.write( "Question 524332: A train leaves the station at 6:00pm traveling west at 80mph. On a parallel track,a second train leaves the station 3 hours later traveling west at 100mph, At what time will second trdain catch up with the first? \n" ); document.write( "

Algebra.Com's Answer #347708 by josmiceli(19441) $\"\"$ $\"About$

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The 1st train to leave has a head start of
\n" ); document.write( " $\"+d%5B1%5D+=+80%2A3+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+240+\"$ mi
\n" ); document.write( "Start a stopwatch when the 2nd train leaves
\n" ); document.write( "the station. Both trains will now travel for
\n" ); document.write( "the same amount of time.
\n" ); document.write( "Let $\"t\"$ = the time on stopwatch for both trains
\n" ); document.write( "Let $\"d\"$ = the distance the 2nd train travels
\n" ); document.write( "-----------------------------------
\n" ); document.write( "For 2nd train:
\n" ); document.write( "(1) $\"+d+=+100t+\"$
\n" ); document.write( "For 1st train:
\n" ); document.write( "(2) $\"+d+-+240+=+80t+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+100t+-+240+=+80t+\"$
\n" ); document.write( "(2) $\"+20t+=+240+\"$
\n" ); document.write( "(2) $\"+t+=+12+\"$
\n" ); document.write( "The 2nd train will catch up to the 1st 12 hours after
\n" ); document.write( "the 2nd train leaves station at 6:00 + 3 hrs = 9:00 PM
\n" ); document.write( "That would be 9:00 AM the next morning.
\n" ); document.write( "check answer:
\n" ); document.write( "(1) $\"+d+=+100t+\"$
\n" ); document.write( "(1) $\"+d+=+100%2A12+\"$
\n" ); document.write( "(1) $\"+d+=+1200+\"$ ( distance from station to where they meet )
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+-+240+=+80t+\"$
\n" ); document.write( "(2) $\"+d+-+240+=+80%2A12+\"$
\n" ); document.write( "(2) $\"+d+=+240+%2B+960+\"$
\n" ); document.write( "(2) $\"+d+=+1200+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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