document.write( "Question 524329: log_2(2m+4)+log_2(m-1)=3 \n" ); document.write( "
Algebra.Com's Answer #347703 by nerdybill(7384)\"\" \"About 
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log_2(2m+4)+log_2(m-1)=3
\n" ); document.write( "log_2(2m+4)(m-1)=3
\n" ); document.write( "(2m+4)(m-1)=2^3
\n" ); document.write( "2m^2-2m+4m-4=8
\n" ); document.write( "2m^2+2m-4=8
\n" ); document.write( "2m^2+2m-12=0
\n" ); document.write( "m^2+m-6=0
\n" ); document.write( "(m+3)(m-2) = 0
\n" ); document.write( "m = {-2, 2}
\n" ); document.write( "we can throw out the -2 solution (extraneous) leaving:
\n" ); document.write( "m = 2\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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