document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524332>Question 524332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves the station at 6:00pm traveling west at 80mph. On a parallel track,a second train leaves the station 3 hours later traveling west at 100mph, At what time will second trdain catch up with the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347702 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train leaves the station at 6:00pm traveling west at 80mph. On a parallel track,a second train leaves the station 3 hours later traveling west at 100mph, At what time will second trdain catch up with the first?\r<BR>\n" );
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document.write( "In 3 hours, the 1st train is 240 miles away (80*3)<BR>\n" );
document.write( "The 2nd train gains on it at 20 mi/hr (100 - 80)<BR>\n" );
document.write( "240/20 = 12 hours from 9 PM to catch up\r<BR>\n" );
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