document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524179>Question 524179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> George leaves his house on his bike at 7:30 AM and averages 5 miles per hour. His wife leaves at 8 AM following the same path averaging 8 miles per hour. At what time will his wife catch George? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347687 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> George speed	5	mph					<BR>\n" );
document.write( "Wife speed	8	mph					<BR>\n" );
document.write( "George speed		07:30					<BR>\n" );
document.write( "Wife speed		08:00					<BR>\n" );
document.write( "Difference in time=		00:30	=>	0.5	hours		<BR>\n" );
document.write( "George speed	will have covered	2.5	miles	before 	wife		starts<BR>\n" );
document.write( "catch up distance=		2.5	miles				<BR>\n" );
document.write( "catch up speed =		8	-5	mph			<BR>\n" );
document.write( "catch up speed =		3	mph				<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed							<BR>\n" );
document.write( "catch up time=		2.5	/	3			<BR>\n" );
document.write( "catch up time=		5/6	hours	=50 minutes\r<BR>\n" );
document.write( "\n" );
document.write( "she will catch up at 8:50 AM\r<BR>\n" );
document.write( "\n" );
document.write( "			<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );