document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524127>Question 524127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem asks to solve the system using the substitution method. The equations are: -2x+y=6 and 4x-2y=5. In the book this is number 12, since they only show the answers in the back of the book to the odd numbers I did number 11. I got that right but I can't figure this one out. Could you please show me the steps to doing this problem. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347607 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equations are:<BR>\n" );
document.write( "-2x + y = 6<BR>\n" );
document.write( " 4x - 2y = 5 <BR>\n" );
document.write( "we will use the 1st equation for substitution, add 2x to both sides and we have:<BR>\n" );
document.write( "y = 2x + 6<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Replace y in the 2nd equation with (2x+6)<BR>\n" );
document.write( "4x - 2(2x+6) = 5<BR>\n" );
document.write( "4x - 4x - 12 = 5<BR>\n" );
document.write( "0 = 5 + 12<BR>\n" );
document.write( "0 = 17; obviously this is not a solvable problem, no solution is the answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );