document.write( "Question 524135: Hello, my question is: Howard has $2.05 in quarters and dimes. He has 4 more quarters than dimes. Find the number he has of each coin.
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Algebra.Com's Answer #347605 by oberobic(2304) $\"\"$ $\"About$

You can put this solution on YOUR website!
With coin problems you have to keep track of the number of coins and the value of the coins.
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\n" ); document.write( "d = number of dimes
\n" ); document.write( "10d = value of the dimes in cents
\n" ); document.write( "q = number of quarters
\n" ); document.write( "25q = value of the quarters in cents
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\n" ); document.write( "10d cents + 25q cents = 205 cents
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\n" ); document.write( "He has 4 more quarters than dimes
\n" ); document.write( "q = d+4
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\n" ); document.write( "Substitute
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\n" ); document.write( "10d + 25(d+4) = 205
\n" ); document.write( "10d + 25d + 100 = 205
\n" ); document.write( "35d = 105
\n" ); document.write( "d = 3
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\n" ); document.write( "q = d+4
\n" ); document.write( "q = 7
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\n" ); document.write( "Check the values to see if this solution is the correct answer.
\n" ); document.write( "10(3) = 30 cents
\n" ); document.write( "25(7) = 175 cents
\n" ); document.write( "30+175 = 205 cents
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: 3 dimes and 7 quarters.
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\n" ); document.write( "Done. \n" ); document.write( "

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