document.write( "Question 523800: A man's age is three times his son's age.Ten years ago he was five times his son's age. By forming two equations and solving them simultaneously,find both of their ages. \n" ); document.write( "
Algebra.Com's Answer #347592 by ankor@dixie-net.com(22740)\"\" \"About 
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A man's age is three times his son's age.Ten years ago he was five times his son's age.
\n" ); document.write( " By forming two equations and solving them simultaneously,find both of their ages.
\n" ); document.write( ":
\n" ); document.write( "Let m = man's present age
\n" ); document.write( "let s = son's present age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"A man's age is three times his son's age\"
\n" ); document.write( "m = 3s
\n" ); document.write( "m - 3s = 0
\n" ); document.write( ":
\n" ); document.write( "\"Ten years ago he was five times his son's age.\"
\n" ); document.write( "m - 10 = 5(s-10)
\n" ); document.write( "m - 10 = 5s - 50
\n" ); document.write( "m - 5s = -50 + 10
\n" ); document.write( "m - 5s = -40
\n" ); document.write( "multiply by -1 to change the signs, add to the first equation
\n" ); document.write( "-m + 5s = 40
\n" ); document.write( "+m - 3s = 0
\n" ); document.write( "------------adding eliminates m, find s
\n" ); document.write( "2s = 40
\n" ); document.write( "s = 40/2
\n" ); document.write( "s = 20 yr is the son's age
\n" ); document.write( "then
\n" ); document.write( "m = 3(20)
\n" ); document.write( "m = 60 is the man's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this in the statement:
\n" ); document.write( "\"Ten years ago he was five times his son's age.\"
\n" ); document.write( "60 - 10 = 5(20-10)
\n" ); document.write( "50 = 5(10); confirms out solutions \n" ); document.write( "
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