document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=524078>Question 524078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 4cm more than its width.  if the area of the rectangle is 60cm^2 find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347537 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x<BR>\n" );
document.write( "length = x+4\r<BR>\n" );
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document.write( "Area = L*W\r<BR>\n" );
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document.write( "x(x+4)=60<BR>\n" );
document.write( "x^2+4x=60<BR>\n" );
document.write( "x^2+4x-60=0<BR>\n" );
document.write( "x^2+10x-6x-60=0<BR>\n" );
document.write( "x(x+10)-6(x+10)=0<BR>\n" );
document.write( "(x+10)(x-6)=0\r<BR>\n" );
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document.write( "choose the positive value since length cannot be negative<BR>\n" );
document.write( "x=6 the width<BR>\n" );
document.write( "Length =10cm </SPAN>\n" );
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