document.write( "Question 524011: The rate of a passenger train exceeds the rate of a freight train by 20 mph. It takes the passenger train 1/2 as much time to travel 160 miles as it does the freight train. Find the rate of each train. \n" ); document.write( "
Algebra.Com's Answer #347519 by lwsshak3(11628)\"\" \"About 
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The rate of a passenger train exceeds the rate of a freight train by 20 mph. It takes the passenger train 1/2 as much time to travel 160 miles as it does the freight train. Find the rate of each train.
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\n" ); document.write( "let x=rate of speed of freight train
\n" ); document.write( "x+20=rate of speed of passenger train
\n" ); document.write( "Travel time=distance/rate of speed
\n" ); document.write( "..
\n" ); document.write( "160/x=2(160/(x+20)
\n" ); document.write( "160x+3200=320x
\n" ); document.write( "160x=3200
\n" ); document.write( "x=3200/160=20
\n" ); document.write( "x+20=40
\n" ); document.write( "ans:
\n" ); document.write( "rate of speed of freight train=20 mph
\n" ); document.write( "rate of speed of passenger train=40 mph
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