document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523996>Question 523996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the parallelogram in the picture and please explain how you did, thank you :)\r<BR>\n" );
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document.write( "http://www.flickr.com/photos/64179385@N07/6299730439/in/photostream<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347508 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "The area of a parallelogram is given by multiplying the measure of the base (the 11 inch side, in your case) times the height (the measure of the dashed line in your case).\r<BR>\n" );
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document.write( "In a right triangle with a 60 degree angle, the side adjacent to the 60 degree angle measures one-half of the hypotenuse.  The side opposite is the square root of 3 times the measure of the side adjacent.  So your little right triangle has sides of 6, 3, and <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 3\sqrt{3}\">.  And <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 3\sqrt{3}\">is the height.  Multiply the height times the measure of the base.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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