document.write( "Question 523978: how would you go about solving x^2-6x+9=100 useing square roots? \n" ); document.write( "
Algebra.Com's Answer #347501 by Edwin McCravy(20055)\"\" \"About 
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document.write( "   x² - 6x + 9 = 100\r\n" );
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document.write( "Factor the left side:\r\n" );
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document.write( "    (x-3)(x-3) = 100\r\n" );
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document.write( "Since the two factors are the same we can write the factor just\r\n" );
document.write( "once with a 2 exponent, that is, as a square of a binomial:\r\n" );
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document.write( "        (x-3)² = 100\r\n" );
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document.write( "Now we use the principle of square roots.  \r\n" );
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document.write( "         x-3 = ±\"sqrt%28100%29\"\r\n" );
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document.write( "         x-3 = ±10\r\n" );
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document.write( "Add 3 to both sides\r\n" );
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document.write( "           x = ±10 + 3\r\n" );
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document.write( "Then we make two equations, one using + and one using -\r\n" );
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document.write( "   x = 10 + 3,     x = -10 + 3\r\n" );
document.write( "   x = 13,         x = -7\r\n" );
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document.write( "Edwin
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