document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523971>Question 523971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a certain triangle the measure of the measure of the second angle is 10 degrees greater than three times the first. the third angle measure is equal to the sum of the measures of the other two. Find the measures of the three angles.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347497 by </B><A HREF=/tutors/aboutme.mpl?userid=lagbens><B>lagbens(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lagbens><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lagbens><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let's call the 1st angle X, so the 2nd angle would be equal to 10+3X.<BR>\n" );
document.write( "the 3rd angle is equal to 10+3X+X which is 10+4x.<BR>\n" );
document.write( "the total measure of the 3 angles of a triangle is 180 degree.<BR>\n" );
document.write( "so we can write X+10+3X+10+4X=180.<BR>\n" );
document.write( "okay we have an equation now, let's solve for \"X\"<BR>\n" );
document.write( "8X+20=180(subtract both side by 20)<BR>\n" );
document.write( "8X=160(divide both side by 8)<BR>\n" );
document.write( "X=20 (1st angle)<BR>\n" );
document.write( "10+3(20)=70 (2nd angle)<BR>\n" );
document.write( "10+4(20)=90 (3rd angle) </SPAN>\n" );
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