document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523971>Question 523971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a certain triangle the measure of the measure of the second angle is 10 degrees greater than three times the first. the third angle measure is equal to the sum of the measures of the other two. Find the measures of the three angles.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347493 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in a certain triangle the measure of the measure of the second angle is 10 degrees greater than three times the first. the third angle measure is equal to the sum of the measures of the other two. Find the measures of the three angles.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=measure of first angle<BR>\n" );
document.write( "3x+10=measure of second angle<BR>\n" );
document.write( "x+(3x+10)=measure of third angle<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+(3x+10)+(x+(3x+10))=180<BR>\n" );
document.write( "x+3x+10+x+3x+10=180<BR>\n" );
document.write( "8x=180-20=160<BR>\n" );
document.write( "x=20º<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "measure of first angle=20º<BR>\n" );
document.write( "measure of second angle=70º<BR>\n" );
document.write( "measure of third angle=90º </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );