document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523937>Question 523937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The measure of one angle is 12° more than one-half of the measure of the other. Find the measure of each angle. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347476 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. The measure of one angle is 12° more than one-half of the measure of the other. Find the measure of each angle.<BR>\n" );
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document.write( "The sum of two angles that are complementary is 90 degrees.<BR>\n" );
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document.write( "Let x = one of two angles<BR>\n" );
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document.write( "(1/2)x + 12 = second angle<BR>\n" );
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document.write( "x + (1/2)x + 12 = 90<BR>\n" );
document.write( "x + (1/2)x = 78<BR>\n" );
document.write( "(2/2)x + (1/2)x = 78<BR>\n" );
document.write( "(3/2)x = 78<BR>\n" );
document.write( "x = (2/3)78<BR>\n" );
document.write( "x = (2)26<BR>\n" );
document.write( "x = 52 degrees (first angle)<BR>\n" );
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document.write( "second angle:<BR>\n" );
document.write( "(1/2)x + 12 = (1/2)52 + 12 = 26 + 12 = 38 degrees<BR>\n" );
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