document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523913>Question 523913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is three times as old as his son. In 12 years tim he will be twice as old. how old is the father now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347468 by </B><A HREF=/tutors/aboutme.mpl?userid=lagbens><B>lagbens(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lagbens><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lagbens><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let's say the son is \"X\" years old<BR>\n" );
document.write( "the father would be \"3X\" years old.<BR>\n" );
document.write( "in 12 years it'll be (X+12=2X).the preceding equation translates the second part of the problem.<BR>\n" );
document.write( "now let's solve for X. X+12=2X, if we subtract X from both side we got X=12.<BR>\n" );
document.write( "so remember the father's age was 3X=3(12), which makes the father's age 36 now.(final answer)<BR>\n" );
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