document.write( "Question 523775: find the equation for the line that contains (0,3)and is perpendicular to the line 6x-2y=1 \n" ); document.write( "

Algebra.Com's Answer #347430 by mananth(16946) $\"\"$ $\"About$

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6 x -2 y = 1
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-2 y = -6 x + 1
\n" ); document.write( "Divide by -2
\n" ); document.write( " y = 3 x + -0.5
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 3.00
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be - 1/3
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\n" ); document.write( "m= - 1/3 ,point ( 0 , 3 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "3 = 0.00 + b
\n" ); document.write( "b= 3
\n" ); document.write( "m= - 1/3
\n" ); document.write( "The required equation is y = - 1/ 3 x + 3
\n" ); document.write( "m.ananth@hotmail.ca
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