document.write( "Question 523791: It took cindy 2 hours to bike from abbott to benson at a constant speed. the return trip took only 1.5 hours because she increased her speed by 6 km/h. how far apart are abbott and benson?\r
\n" ); document.write( "\n" ); document.write( "I would like to know how you would solve a problem like this using the distance formula: speed*time=distance
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Algebra.Com's Answer #347425 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
It took cindy 2 hours to bike from abbott to benson at a constant speed. the return trip took only 1.5 hours because she increased her speed by 6 km/h. how far apart are abbott and benson?
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\n" ); document.write( "A to B DATA:
\n" ); document.write( "time = 2 hrs ; rate = r kmh ; distance = r*t = 2r km
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\n" ); document.write( "B to A DATA:
\n" ); document.write( "time = 1.5 hrs; r+6 kmh ; distance = r*t = 1.5(r+6) km
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "2r = 1.5(r+6)
\n" ); document.write( "2r = 1.5r + 9
\n" ); document.write( "0.5r = 9
\n" ); document.write( "r = 18 kmh
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\n" ); document.write( "Distance from A to B = 2r = 2*18 = 36 km
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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