document.write( "Question 523765: if you have a sphere that is 6\" in diameter and it wieghs 1.67 lbs, what would be the diameter of a 45 lb. sphere? \n" ); document.write( "
Algebra.Com's Answer #347411 by mananth(16946) You can put this solution on YOUR website! Volume of sphere = 4/3 *pi*r^3\r \n" ); document.write( "\n" ); document.write( "Volume = 4/3 *pi*3^3 \n" ); document.write( "Volume = 113.09 \r \n" ); document.write( "\n" ); document.write( "this weighs 1.67 lbs\r \n" ); document.write( "\n" ); document.write( "1.67 lbs -------------- 113.09 \n" ); document.write( "45 lb------------------x \n" ); document.write( "x= 45*113.09/1.67\r \n" ); document.write( "\n" ); document.write( "3047.33 is the volume\r \n" ); document.write( "\n" ); document.write( "V= (4/3)*pi*r^3 \n" ); document.write( "3V/4*pi=r^3 \n" ); document.write( "3*3047.33/4*pi=r^3\r \n" ); document.write( "\n" ); document.write( "r^3=7180.33 \n" ); document.write( "r = cuberoot(7180.33) \n" ); document.write( "r=19.29 in \n" ); document.write( " |