document.write( "Question 523730: Use the quadratic formula to solve for Q in the equation 3Q(to the power 2)-6=0 \n" ); document.write( "
Algebra.Com's Answer #347405 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
a= 3 ,b= 0 ,c= -6
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 0 + 72
\n" ); document.write( "b^2-4ac= 72
\n" ); document.write( "\"q=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"q1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"q1=%28-12%2B21%29%2F%286%29\"
\n" ); document.write( "q1=( 0 + 8.49 )/ 6
\n" ); document.write( "q1= 1.41 1 41/99
\n" ); document.write( "q2=( 0 -8.49 ) / 6
\n" ); document.write( "q2= -1.41 \r
\n" ); document.write( "\n" ); document.write( "(1.41,-1.41)
\n" ); document.write( "
\n" ); document.write( "
\n" );